Answer:
2.27secs
Explanation:
The car will take 2.27secs to reach a speed of 10 ft/s.
Kindly go through the attached files for a step by step solution that will show you how the answer was gotten and the normal reaction of both the front and rear wheels.
Answer:
Pressure = 
Explanation:
The pressure is calculated by Bernoulli's equation.

Solving it for P2

Now inserting values
P1 = 0 as it is given that initial point is at atmospheric point.
d= density = 2.05 sl/ft3
Vi = 200 mph = 293.33 ft/s
Vf = 273 mph = 400.4 ft/s
Putting these values

Changing the units to pounds per square foot

Explanation:
The two types of furnaces used in steel production are:
<u>Basic oxygen furnace </u>
In basic oxygen furnace, iron is combined with the varying amounts of the steel scrap and also small amounts of the flux in the Blast Furnace. Lance is introduced in vessel and blows about 99% of the pure oxygen causing rise in temperature to about 1700°C. This temperature melts scrap and the impurities are oxidized and results in the liquid steel.
<u>Electric arc furnace</u>
Electric arc furnace reuses existing steel. Furnace is charged with the steel scrap. It operates on basis of electrical charge between the two electrodes providing heat for process. Power is supplied through electrodes placed in furnace, which produce arc of the electricity through scrap steel which raises temperature to about 1600˚C. This temperature melts scrap and the impurities can be removed through use of the fluxes and results in the liquid steel.
Answer:


Given:

operating temperature of heat engine, 

Solution:
For a reversible cycle, maximum efficiency,
is given by:



Now, on re designing collector, maximum temperature,
changes to
, so, the new maximum efficiency,
is given by:



Question:
In a typical transmission line, the current I is very small and the voltage V is very large. A unit length of the line has resistance R.
For a power line that supplies power to 10 000 households, we can conclude that
a) IV < I²R
b) I²R = 0
c) IV = I²R
d) IV > I²R
e) I = V/R
Answer:
d) IV > I²R
Explanation:
In a typical transmission line, the current I is very small and the voltage V is very high as to minimize the I²R losses in the transmission line.
The power delivered to households is given by
P = IV
The losses in the transmission line are given by
Ploss = I²R
Therefore, the relation IV > I²R holds true, the power delivered to the consumers is always greater than the power lost in the transmission line.
Moreover, losses cannot be more than the power delivered. Losses cannot be zero since the transmission line has some resistance. The power delivered to the consumers is always greater than the power lost in the transmission.