Answer: C. Problem identification, solution design, implementation, evaluation.
Explanation:
Answer:
Load carried by shaft=9.92 ft-lb
Explanation:
Given: Power P=4.4 HP
P=3281.08 W
<u><em>Power: </em></u>Rate of change of work with respect to time is called power.
We know that P=![Torque\times speed](https://tex.z-dn.net/?f=Torque%5Ctimes%20speed)
rad/sec
So that P=![\dfrac{2\pi NT}{60}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%20NT%7D%7B60%7D)
So 3281.08=![\dfrac{2\pi \times 2329\times T}{60}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%20%5Ctimes%202329%5Ctimes%20T%7D%7B60%7D)
T=13.45 N-m (1 N-m=0.737 ft-lb)
So T=9.92 ft-lb.
Load carried by shaft=9.92 ft-lb
My answer says there is a link but not,there isn’t so here a photo of my answer.
I believe it’s A bit I. could be wrong