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3 years ago

10

A wooden pallet carrying 540kg rests on a wooden floor. (a) a forklift driver decides to push it without lifting it.what force m

ust be applied to just get the pallet moving.

1 answer:

Daniel [21]3 years ago

7 0

Answer:

F=ms × m× g

F= 0.28 × 540 × 9.81

F= 1483.272 N

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What is the zone that has just been added to the exchange zone where athletes may now hand off the baton

Vanyuwa [196]

Answer:

The zone where athletes may hand off baton in exchange zone is the changeover zone.

Explanation:

A relay race is a track event that involves the exchange of baton among a set of athletes. The baton is majorly exchange within the exchange zone which is 20 meters long. The exchange zone is made up on two other zones: acceleration zone and changeover zone.

Acceleration zone is the region of the track that allows the athlete to take the next leg to start increasing speed before collecting the baton.

Changeover zone is the section where baton exchange between athletes takes place. The baton should only be exchanged within the changeover zone.

8 0

4 years ago

A flow of 12 m/s passes through a 6 m wide, 2 m deep rectangular channel with a bed slope of 0. 001. If the mean velocity of flo

prohojiy [21]

Answer:

manning's coefficient is 0.0357

Explanation:

Given:

Velocity of flow, v = 12 m/s

Width of the channel, b = 6 m

Depth of the channel, d = 2 m

bed slope, s = 0.001

mean velocity of flow, V = 1 m/s

now, the velocity is given as:

$V= \frac{1}{n}R^{\frac{2}{3}}S^{\frac{1}{2}}$

where,

n is the manning's coefficient

R is hydraulic mean depth

R = (Area of the channel) / (wetted Perimeter of the channel)

now,

R = (2 × 6) / ((2 × 2) + 6)

or

R = 12 / 10 = 1.2 m

now, on substituting the values in the equation for velocity, we get

$1= \frac{1}{n}1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

or

$n= 1.2^{\frac{2}{3}}(0.001)^{\frac{1}{2}}$

or

n = 0.0357

hence, the value of manning's coefficient is 0.0357

8 0

3 years ago

Which of the following characteristics would not give animals an advantage in the ocean?

Taya2010 [7]

I believes it’s long body hair

3 0

3 years ago

Proper handling of blueprints includes which of the following

marta [7]

Answer:

folding plans neatly after use

3 0

3 years ago

The diffusion coefficients for species A in metal B are given at two temperatures:

Kruka [31]

Answer:

a) 149 kJ/mol, b) 6.11*10^-11 m^2/s ,c) 2.76*10^-16 m^2/s

Explanation:

Diffusion is governed by Arrhenius equation

$D = D_0e^{\frac{-Q_d}{RT} }$

I will be using R in the equation instead of k_b as the problem asks for molar activation energy

I will be using

$R = 8.314\ J/mol*K$

and

°C + 273 = K

here, adjust your precision as neccessary

Since we got 2 difusion coefficients at 2 temperatures alredy, we can simply turn these into 2 linear equations to solve for a) and b) simply by taking logarithm

So:

$ln(6.69*10^{-17})=ln(D_0) -\frac{Q_d}{R*(1030+273)}$

and

$ln(6.56*10^{-16}) = ln(D_0) -\frac{Q_d}{R*(1290+273)}$

You might notice that these equations have the form of

$d=y-ax$

You can solve this equation system easily using calculator, and you will eventually get

$D_0 =6.11*10^{-11}\ m^2/s\\ Q_d=1.49 *10^3\ J/mol$

After you got those 2 parameters, the rest is easy, you can just plug them all including the given temperature of 1180°C into the Arrhenius equation

$6.11*10^{-11}e^{\frac{149\ 000}{8.143*(1180+273)}$

And you should get D = 2.76*10^-16 m^/s as an answer for c)

5 0

3 years ago