1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SIZIF [17.4K]
3 years ago
9

Jayla has a USB stick that transfers data at 2.4 x 10^9 bytes per second. Her modem transfers data at 1.2 x 10^7 bytes per secon

d. Which statement is true?
A.There is no way to compare the transfer rates.

B.The transfer rate of the USB is 2 times the transfer rate of the Modem.

C.The transfer rate of the USB stick is 200 times the trasnfer rate of the modem

D.The transfer rate of the USB stick is 2,000 times the transfer rate of the modem
Mathematics
2 answers:
qwelly [4]3 years ago
3 0
\cfrac{2.4*10^{9}}{1.2*10^{7}}=2*10^2=200

<span>C.The transfer rate of the USB stick is 200 times the trasnfer rate of the modem</span>
tresset_1 [31]3 years ago
3 0

Answer: C.The transfer rate of the USB stick is 200 times the transfer rate of the modem .

You might be interested in
The math clubs car can travel 9 meters in a second. The race track for the soap box derby is 63 meters long. How many seconds wi
zhenek [66]

Answer: it will take 7 seconds

Step-by-step explanation: 9 x 7 = 63

5 0
3 years ago
Two hikers stopped for a snack. They shared 2/3 of a pound of trail mix. If the hikers shared the trail mix equally, how much tr
allochka39001 [22]

each hiker gets 1 1/2

i hope this helped

5 0
3 years ago
Read 2 more answers
Which marine fish stock assessment method involves trawling by scientists to collect data, which are then used to infer changes
Snowcat [4.5K]

Answer:

sampling

Step-by-step explanation:

6 0
3 years ago
Can anyone help me with this
stiv31 [10]

Answer:

12

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
HELP ME OUT PLEASE!
atroni [7]

Answer:

6.85 × 10⁷

Step-by-step explanation:

The purpose of scientific notation is for scientists to write very large, or very small, numbers with ease.

Calculating scientific notation for a positive integer is simple, as it always follows this notation:

a x 10b

Follow the steps below to see how 68,500,000 is written in scientific notation.

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 68,500,000

New Number: 6.8500000

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number:6.8500000Decimal Count:1234567

There are 7 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 6.85 (Please notice any zeroes on the end have been removed)

b = 7

Now the whole thing:

6.85 x 107

Step 4

Check your work:

107 = 10,000,000 x 6.85 = 68,500,000

6 0
2 years ago
Other questions:
  • Write the expanded form of 9,003,840,165
    13·2 answers
  • 7. What is the surface area of the sphere?
    7·1 answer
  • How many models of 100 do you need to model 8500? enter the number. then complete the explanation.​
    14·1 answer
  • 3 = 3<br> O True<br> O False
    5·1 answer
  • PLSSSS PLSSS HELPPPP MEEEEE ASAPPPPP I WILLLLL GIVE BRAINLIEST!!!!!!!
    11·1 answer
  • Special precision bolts are made by another machine. Write this inequality as a compound
    13·1 answer
  • the value of a particular investment follows a pattern of exponential growth. in the year 2000, you invested money in a money ma
    14·1 answer
  • numbers like 10, 100, 1,000, and so on are called ___________.what is the correct term or number to complete the sentence.
    5·1 answer
  • Angela uses a force of 25 Newtons to lift her grocery bag while doing 50 Joules of work. How far did she lift the grocery bags?
    9·1 answer
  • Which of the following is not a perfect square?<br> OA, 1<br> OB) 2<br> OC) 4<br> OD) 9
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!