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Eva8 [605]
3 years ago
14

Last autumn, julia noticed something interesting as she blew up spherical balloons for harris's birthday party. she calculated t

he volume of a balloon with a radius of 4 cm and then the volume of a balloon with a radius of 8cm. did she discover that the volume is twice as big when the radius is doubled?
Mathematics
2 answers:
zmey [24]3 years ago
8 0

She would not find out that the volume is twice as big when the radius is doubled.

Vikki [24]3 years ago
4 0
To find whether the volume would be doubled when the radius is,we can find the volume of the two balloons.

The formula of a sphere is:
\frac{4}{3} \pi \: {r}^{3}
Let's take 丌 as 3.14

The volume of the balloon with 4cm radius:
\frac{4}{3}(3.14)  \times  {4}^{3}  \\  = 4.18667 \times 64 \\  = 267.94688

The volume of the balloon with 8cm radius:
\frac{4}{3}(3.14)  \times  {8}^{3}  \\  = 4.18667 \times 512 \\  = 2143.57504
As we can see,
267.94668 × 2 = 535.89 ≠2145.56

Thus,she wouldn't discover that the volume is twice as big when the radius is doubled.

Hope it helps!
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Solve the proportion y/10=3/5
mamaluj [8]

Answer:

y = 6

Step-by-step explanation:

When    \frac{y}{10} = \frac{3}{5}

             y = \frac{3 * 10}{5}

                = \frac{30}{5}

            y = 6

Hope that help :)

8 0
3 years ago
Find the area of the trapezoid.
Usimov [2.4K]

Answer:

\large\boxed{A=54\ m^2}

Step-by-step explanation:

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdor h

<em>b₁, b₂</em> - <em>bases</em>

<em>h</em><em> - height</em>

We must use the Pythagorean theorem:

x^2+8^2=10^2

x^2+64=100              <em>subtract 64 from both sides</em>

x^2=36\to x=\sqrt{36}\\\\x=6\ m

We have <em>b₁ = 6 + 6 = 12m</em>, <em>b₂ = 6m</em> and <em>h = 8m</em>.

Substitute:

A=\dfrac{12+6}{2}\cdot6=\dfrac{18}{2}\cdot6=(9)(6)=54\ m^2

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3 years ago
I need help. i dont get it
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It is graph b, its negative
6 0
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Factor x^3 -7x^2 -5x+35 by grouping. what is the resulting expression
Anni [7]

Answer:

(x-7) (x^2-5)

Step-by-step explanation:

x^3 -7x^2 -5x+35

Make 2 groups

x^3 -7x^2      -5x+35

Factor x^2 from the first group and -5 from the second group

x^2 (x-7)       -5(x-7)

Now factor (x-7) out

(x-7) (x^2-5)

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Answer:

Step-by-step explanation:

In school i did these but i have no clue how to do them.I will try though:)

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