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gizmo_the_mogwai [7]
3 years ago
5

Help! im in class right now and dont have much time!

Mathematics
2 answers:
Hatshy [7]3 years ago
6 0

Answer:

\frac{1}{m^{8} }

Step-by-step explanation:

m^{-8} p^{0}

m^{-8} 1       ∴Zero power of any number is equal to 1

\frac{1}{m^{8} }            

Harman [31]3 years ago
4 0

Answer:

D. \frac{1}{m^8}

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f(x) = - | x + 2 | + 2

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Find the median of the following data 20,14,6,25,18,13,19,10,9,12
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Step-by-step explanation:

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Read 2 more answers
Please help me with this! I will rate you brainliest!!
lesya [120]

do 6x8.(theres two x's and two y's)

3 0
3 years ago
Read 2 more answers
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
1 year ago
Helppppppppp but no link
Kobotan [32]

Answer:

the third graph, or c.

6 0
3 years ago
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