Here are a few things you'll need to know for this question:
- Domain: <u>The list of x-values that are possible on a line.</u>
- Range: <u>The list of y-values that are possible on a line.</u>
- Interval Notation: <u>Shows the domain/range using the endpoints</u>. Brackets mean that the endpoint is included, parentheses mean the endpoint is excluded. Ex: (2,10]. 2 is excluded, 10 is included.
- Closed Circles: <u>The endpoint is included.</u>
- Open Circles: <u>The endpoint is excluded.</u>
So firstly, let's look at the domain. We see that there is a closed circle at x = -2 and an open circle at x = 5. Using what we know, <u>the interval notation of the domain is [-2,5).</u>
Next, let's look at the range. We see that there is a closed circle at y = -5 and an open circle at y = 2. Using what we know, <u>the interval notation of the range is [-5,2).</u>
Answer:
C (x, y) -> (x + 7, y + 8); scale factor = 3
Step-by-step explanation:
The translation can be found by subtracting the coordinates of the original center from those of the center of the image. The scale factor will be the ratio of the radii.
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<h3>translation</h3>
We note the center coordinates are I(-3, -6) and I'(4, 2). Then the translation is ...
I' -I = (4, 2) -(-3, -6) = (4 +3, 2 +6) = (7, 8)
(x, y) ⇒ (x +7, y +8)
<h3>scale factor</h3>
The radius of each circle can be found by counting the grid squares from the center to the circle. It works best to do this along a horizontal or vertical line.
The radius of circle I is 2; the radius of circle I' is 6. The scale factor is ...
scale factor = 6/2 = 3
Answer:
1
Step-by-step explanation:
