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hodyreva [135]
3 years ago
12

A ladder 17 feet long is leaning against a wall. The bottom of the ladder is 8 feet from the base of the wall. How far up the wa

ll is the top of the ladder?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer: the top of the ladder is 15 feet up the wall

Step-by-step explanation:

The attached photo shows the triangle ABC formed by the ladder and the wall. It is a right angle triangle because one of its angles is 90 degrees. The ladder is the hypotenuse of the triangle. To determine how far up the wall that the top of the ladder is,we would find BC by applying Pythagoras theorem

Hypotenuse^2 = opposite ^2 + adjacent^2

17^2 + 8^2 + BC^2

BC^2 = 289 - 64 = 225

BC = √225 = 15

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

P(0) =\frac{1200}{1+11}

P(0) =\frac{1200}{12}

P(0) = 100

Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

t = 30

P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

Solving (c): \lim_{t \to \infty} P(t)

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

P(\infty) = \frac{1200}{1 + 11 * 0}

P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

5 0
3 years ago
The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole
deff fn [24]

Answer:

The length of the flagpole be 41.2 ft .

Option (A) is correct .

Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

A flagpole casts a shadow of 15 ft .

Now by using the trignometric identity .

tan \theta = \frac{Perpendicular}{Base}

\ theta = 70^{\circ}

tan\ 70^{\circ} = \frac{AB}{BC}

BC = 15 ft

tan 70° = 2.75 (Approx)

2.75 = \frac{AB}{15}

AB = 2.75 × 15

     = 41.2 ft

Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

4 0
3 years ago
Read 2 more answers
Pls help i will give a good amount of points
AleksandrR [38]
The area is 10,994.39
3 0
3 years ago
PLEASE HELP ME, MY MOM WILL KILL ME IF I DONT HAVE THEESE ASSIGNMENTS DONE
Schach [20]

Answer:

A. 2

B. 10/3

C. 8/3

D. 2/3

Step-by-step explanation: put the whole #and make it into a fraction like this e.g.

6/1 • 1/3 = 6/3 simplifies to 2

3 0
3 years ago
Keira goes shopping at a supermarket
Damm [24]
What is the rest of it
6 0
3 years ago
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