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3 years ago

What is the main organ in the respiratory System?

Physics

2 answers:

sladkih [1.3K]3 years ago

4 0

The main organ of the respiratory system is Lungs.

-Dominant- [34]3 years ago

3 0

The major organs of the respiratory system are the lungs

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An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?

Maksim231197 [3]

Answer:

$88.3ms {}^{ - 2}$

or 88.3m/s^2

Explanation:

Using suvat where we list everything that we are given

s=49m

u=0m/s

v=93m/s

a=?

t=we are not given this value, so we don't use

using a formula that doesn't involve time:

$v {}^{2} = u {}^{2} + 2as$

rearranging to find acceleration by subtracting u^2 on both sides

$v {}^{2} - u {}^{2} = 2as$

then dividing 2s on both sides

$\frac{v {}^{2} - u {}^{2} }{2s} = a$

$\frac{(93) {}^{2} - (0) {}^{2} }{2 \times(49) } = 88.3ms {}^{ - 2}$

so the acceleration is 88.3ms^-2 (1dp)

3 0

3 years ago

When an earthquake occurs, two types of sound waves are generated and travel through the earth. The primary, or P, wave has a sp

Zielflug [23.3K]

Answer: $d=7.94\times 10^5\ m$

Explanation:

Given

Speed of Primary wave $v_1=8\ km/s$

Speed of secondary wave $v_2=4.5\ km/s$

difference in timing of two waves are $77.2\ s$

Suppose both travel a distance of d km then

$t_1=\frac{d}{8}\quad \ldots (i)$

$t_2=\frac{d}{4.5}\quad \ldots (ii)$

Subtract (ii) from (i)

$\frac{d}{4.5}-\frac{d}{8}=77.2$

$d[\frac{1}{4.5}-\frac{1}{8}]=77.2$

$d[0.0972]=77.2$

$d=794.23\ km$

$d=7.94\times 10^5\ m$

7 0

3 years ago

. A newly discovered planet has three times the mass and five times the radius of Earth. What is the ratio of the acceleration d

NikAS [45]

Answer:

0.12

Explanation:

The acceleration due to gravity of a planet with mass M and radius R is given as:

g = (G*M) / R²

Where G is gravitational constant.

The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg

The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m

Therefore:

g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²

g(planet) = 1.18 m/s²

Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:

g(planet)/g(earth) = 1.18/9.8 = 0.12

3 0

3 years ago

Roaring of a lion is different from the sound of the mosquito why?

Soloha48 [4]

Answer:

The roaring of the lion is louder and has low pitch than the sound produced by a mosquito. Hence, they sound so different

4 0

3 years ago

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how

Lunna [17]

Answer:

$9.5\; {\rm m}$ .

Explanation:

Let $u$ and $v$ denote the velocity of this hockey player before and after stopping, respectively. The question states that $u = 9.5\; {\rm m\cdot s^{-1}}$ and implies that $v = 0\; {\rm m\cdot s^{-1}$ since the hockey player has come to a stop.

The duration of this acceleration is $t = 2\; {\rm s}$ .

Since the acceleration of this hockey player was constant, SUVAT equation would apply. In particular, the SUVAT equation $x = (1/2)\, (v + u) \, (t)$ gives the displacement $x$ of this hockey player during that $2\; {\rm s}$ of acceleration:

$\begin{aligned} x &= \frac{1}{2}\, (9.5\; {\rm m\cdot s^{-1}} + 0\; {\rm m\cdot s^{-1}})\, (2\; {\rm s}) = 9.5\; {\rm m} \end{aligned}$ .

In other words, this hockey player would have travelled $9.5\; {\rm m}$ while stopping.

8 0

2 years ago