A standard numbered cube (die) has six faves numbered 1, 2, 3, 4, 5, 6
Three are even 2, 4, 6 and three are odd 1, 3, 5
P(even) = 3/6
P(odd) = 3/6
So for a fair die an odd number is equally likely as an even number
9514 1404 393
Answer:
Step-by-step explanation:
It's pretty straightforward. You want ...
f(x) - g(x)
Substituting the given function definitions gives ...
Answer:
Hi there, you can use Pitagoras relationship to solve this up (Without using any other "tool".
Point A is located wheter in (-6,8) or could be located in (-6,8)
Step-by-step explanation:
Point A is 10 units away from the origin, and its x coordinate is -6, using this information, you can draw a triangle from 0 to -6 (the basis) and using 10 as the hypotenuse, so, you have this equation:
solving for Y variable, you have this
y=±
Note the combined sing ±, meaning that y=8 is a valid answer and that y= -8 is also a valid answer.
Hope It helps
Answer: A. 12
WORKINGS
Given the data set for 11 seasons of play14, 22, 19, 21, 30, 32, 25, 15, 16, 27, 28
Quartiles (usually 3 in number; Q1. Q2 and Q3) divide a rank-ordered data set into four equal parts
14, 22, 19, 21, 30, 32, 25, 15, 16, 27, 28
First order the data set by rank
12, 14, 16, 19, 21, 22, 25, 27, 28, 30, 32
Q1 is the first quartile
Q2 is the second quartile
Q3 is the third quartile
Interquartile range = Q3 – Q1
The median value in the set, Q2 = 22
First half of the rank-ordered data set is therefore 12, 14, 16, 19, 21
While the Second half of the rank-ordered data set is 25, 27, 28, 30, 32
The median value in the first half of the set, Q1 = 16
The median value in the second half of the set, Q3 = 28
Interquartile range = Q3 – Q1
Therefore, interquartile range = 28 – 16
= 12
The interquartile range of the data is 12