For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1, and in this case:
-m/4=-1
-m=-4
m=4, so the slope of the perpendicular line is 4 so we have thus far:
y=4x+b, using point (-4,3) we can solve for the y-intercept, "b"
3=4(-4)+b
3=-16+b
19=b, so our line is:
y=4x+19
Hello, this is a linear problem so we are working with y = mx + b
The problem tells us:
y = total cost
x = the megabytes of data that she used in a month
b = y-intercept, which is the initial value
The problem asks "Which part of the graph will represent the cost per megabyte of data used in each plan?"
It is asking for cost per megabyte... This is a rate. and m = slope = rate
So lets, reiterate.
y = total cost
x = the megabytes of data that she used in a month
b = y-intercept, which is the initial value
m = slope = rate = cost per megabyte of data used
Answer: The slopes of the two lines.
The descriminant is b^2-4ac so for 26 it would be -5^2 - 4 (1) (7). The quadratic formula is -B plus or minus the square root of b squared minus 4ac over 2a
A center at q scale factor of 1/2
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).
There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)
Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).
95 ft. squared is the area of the entire figure. Hope this helped you.
