What equation is perpendicular to y = 3/2x-3 and passes through (-1, 2)?
1 answer:
Answer:
y=2/3x-16/3
Step-by-step explanation:
Find perpendular by using negative reciprocal. Then plug in your x and y points into that equation, y=-2/3x-3 --> Then make y=2 and x=-1 --> 2=2/3(-1)+b
solve for b and ur done.
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