Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
B=4676+10043 c=b-2160 answer equals b+c
I hope this is helpful I am trying not to say the exact answer but to teach you instead
Initially there were 12 dogs
dogs left at the end of day =4
number of dogs sold=12-4=8
price of one dog=$104
price of 8 dogs = 104*8= $832
initially there were 8 cats
cats left at the end of day =5
number of cats sold =8-5=3
price of one cat= $25
price of 3 cats =25*3= $75
ratio of sales for dogs to cats = 832/75
Answer:
graph shown in image below
Step-by-step explanation:
