Answer:

Step-by-step explanation:
given,
angular deceleration, α = -0.5 rad/s²
final angular velocity,ω_f = 0 rad/s
angular position, θ = 6.1 rad
angular position at 3.9 s = ?
now, Calculating the initial angular speed




now, angular position calculation at t=3.9 s



Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.
Answer:
B. 2nd Play and B. 2nd Play
Step-by-step explanation:
#1) Going negative means going backwards.
-8<10.5
#2) Absolute value means making all numbers INSIDE the two lines positive.
I-8I = 8
I10.5I = 10.5
Check the picture below
now, <span>26°35' is just 26bdegrees and 35 minutes
your calculator most likely will have a button [ </span><span>° ' " ] to enter degrees and minutes and seconds
there are 60 minutes in 1 degree and 60 seconds in 1 minute
so.. you could also just convert the 35' to 35/60 degrees
so </span>
![\bf 26^o35'\implies 26+\frac{35}{60}\implies \cfrac{1595}{60}\iff \cfrac{319}{12} \\\\\\ tan(26^o35')\iff tan\left[ \left( \cfrac{391}{12} \right)^o \right]](https://tex.z-dn.net/?f=%5Cbf%2026%5Eo35%27%5Cimplies%2026%2B%5Cfrac%7B35%7D%7B60%7D%5Cimplies%20%5Ccfrac%7B1595%7D%7B60%7D%5Ciff%20%5Ccfrac%7B319%7D%7B12%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%2826%5Eo35%27%29%5Ciff%20tan%5Cleft%5B%20%5Cleft%28%20%5Ccfrac%7B391%7D%7B12%7D%20%5Cright%29%5Eo%20%5Cright%5D)
now, the angle is in degrees, thus, make sure your calculator is in Degree mode
Answer:
7.222 (repeating)
Step-by-step explanation:
8 + 10 + 8 + 5 + 4 + 7 + 5 + 10 + 8 = 65
1 2 3 4 5 6 7 8 9
65 / 9 = 7.222 (repeating)