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VLD [36.1K]
2 years ago
6

Please help!!! need answered quick​

Mathematics
1 answer:
e-lub [12.9K]2 years ago
4 0
That looks hard lol
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Which rule would best describes this pattern 8,4,10,6,12,8,14
irinina [24]

Answer:

Subtract 4 and then add 6.

Step-by-step explanation:

8-4=4

4+6=10

10-4=6

6+6=12

12-4=8

8+6=14

The rule for this pattern can be subtracting 4, and then adding 6.

3 0
3 years ago
Simplify the expression: –3(–7 + 3z)
aleksandrvk [35]

Hey there! I'm happy to help!

We want to multiply each term inside the parentheses by the number on the outside.

-3(-7)=21

-3(3z)=-9z

Therefore, our expression is 21-9z.

Now you know how to use the distributive property! Have a wonderful day! :D

5 0
3 years ago
In reciprocal is the denominator one unit
docker41 [41]
Not always if you're saying it will always be something like 1/2 becomes 2/1 with a unit of one. It's just flipped, so 2/6 will be 6/2, 4/5 becomes 5/4, 22/16 becomes 16/22 etc. That is all there is to it. Make sure you simplify your answers.
5 0
3 years ago
If y varies inversely as x and y=24 when x=8, find y when x is 4
olga2289 [7]
Y would equal 12 if x were to equal 4. You can think of it as a proportion.
6 0
3 years ago
Solve each inequality, and then drag the correct solution graph to the inequality.
Nesterboy [21]

The correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

4(9x-18)>3(8x+12)

First, clear the brackets,

36x-72>24x+36

Then, collect like terms

36x-24x>36+72\\12x >108

Now divide both sides by 12

\frac{12x}{12} > \frac{108}{12}

∴ x > 9

For the second inequality

-\frac{1}{3}(12x+6) \geq -2x +14

First, clear the fraction by multiplying both sides by 3

3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)

-1(12x+6) \geq -6x +42

Now, open the bracket

-12x-6 \geq -6x +42

Collect like terms

-6 -42\geq -6x +12x

-48\geq 6x

Divide both sides by 6

\frac{-48}{6} \geq \frac{6x}{6}

-8\geq x

∴ x\leq  -8

For the third inequality,

1.6(x+8)\geq 38.4

First, clear the brackets

1.6x + 12.8\geq 38.4

Collect likes terms

1.6x \geq 38.4-12.8

1.6x \geq 25.6

Divide both sides by 1.6

\frac{1.6x}{1.6}\geq  \frac{25.6}{1.6}

∴ x \geq  16

Let the graphs be A, B and C from left to right

The first graph (A) shows x\leq  -8 and this matches the 2nd inequality

The second graph (B) shows x \geq  16 and this matches the 3rd inequality

The third graph (C) shows x > 9 and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

Learn more here: brainly.com/question/17448505

8 0
2 years ago
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