Please help!!! need answered quick<br>

Which rule would best describes this pattern 8,4,10,6,12,8,14

irinina [24]

Answer:

Subtract 4 and then add 6.

Step-by-step explanation:

8-4=4

4+6=10

10-4=6

6+6=12

12-4=8

8+6=14

The rule for this pattern can be subtracting 4, and then adding 6.

3 0

3 years ago

Simplify the expression: –3(–7 + 3z)

aleksandrvk [35]

Hey there! I'm happy to help!

We want to multiply each term inside the parentheses by the number on the outside.

-3(-7)=21

-3(3z)=-9z

Therefore, our expression is 21-9z.

Now you know how to use the distributive property! Have a wonderful day! :D

5 0

3 years ago

In reciprocal is the denominator one unit

docker41 [41]

Not always if you're saying it will always be something like 1/2 becomes 2/1 with a unit of one. It's just flipped, so 2/6 will be 6/2, 4/5 becomes 5/4, 22/16 becomes 16/22 etc. That is all there is to it. Make sure you simplify your answers.

5 0

3 years ago

If y varies inversely as x and y=24 when x=8, find y when x is 4

olga2289 [7]

Y would equal 12 if x were to equal 4. You can think of it as a proportion.

6 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Please help!!! need answered quick​

Please help!!! need answered quick