3x^2 + 2x - 6 if x = -2

=3(-2)^2 + 2(-2) - 6
=12 - 4 - 6
= 2

5x^2 + 6x - 2 if x = -2

=5(-2)^2 + 6(-2) - 2
=20 - 12 - 2
= 6

-2x^3 + 2x^2 if x = 2

= -2(2)^3 + 2(2)^2
= -16 + 8
= -8

5 0

4 years ago

After 1 month your $120 becomes $121.20. what is the yearly interest rate?

Rasek [7]

Answer $14.40 hope this helps

5 0

4 years ago

Help find area of parallelogram!!!

Anika [276]

$\bf \textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{sin(75^o)}{17}=\cfrac{sin(D)}{10}\implies \cfrac{10sin(75^o)}{17}=sin(D) \\\\\\ sin^{-1}\left[ \cfrac{10sin(75^o)}{17} \right]=D\implies 34.6\approx D$

since all interior angles in a triangle must be 180°, that means that C = 180 - 75 - 34.6 = 70.4. Let's find AD, which is the other sides pair length.

$\bf \cfrac{sin(75^o)}{17}=\cfrac{sin(70.4^o)}{AD}\implies ADsin(75^o)=17sin(70.4^o) \\\\\\ AD=\cfrac{17sin(70.4^o)}{sin(75^o)}\implies AD\approx 16.58$

now, check the picture below, let's find the altitude of the parallelogram.

$\bf sin(34.6^o)=\cfrac{\stackrel{opposite}{h}}{\stackrel{hypotenuse}{16.58}}\implies 16.58sin(34.6^o)=h\implies 9.4\approx h \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a parallelogram}\\\\ A=bh~~ \begin{cases} b=base\\ h=height\\ \cline{1-1} b=17\\ h=9.4 \end{cases}\implies A=(17)(9.4)\implies A=159.8$

6 0

4 years ago