3 years ago

Whats the answer for each of these

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

I don't know sorry I wish I new

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the answer is cos(C).

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A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relatio

olasank [31]

This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
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t=1.702
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87.5 miles is the actual distance

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Which equation is equivalent to x^2 +24-8=0?

Kipish [7]

Answer:

D) is your correct answer

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For the equation given below, evaluate y′ at the point (−2,2) xe^y−4y=2x−4−2e^2

jeka94

Implicit differentiation
chain rule is important here

I'll show the steps partially
$e^y+xe^yy'-4y'=2$
$xe^yy'-4y'=2-e^y$
$y'(xe^y-4)=2-e^y$
$y'=\dfrac{2-e^y}{xe^y-4}$
now evaluate for (-2,2)
x=-2 and y=2
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$y'=\dfrac{2-e^2}{-2e^2-4}$
$y'=\dfrac{e^2-2}{2e^2+4}$
that's it, simplest form

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3 years ago