What is the value of the expression for h= -4

Mathematics

1 answer:

Lilit [14]3 years ago

7 0

where's the rest of the question

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The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the

kipiarov [429]

Interquartile Range (IQR) = $Q_3-Q_1$ , with $Q_3$ as the upper quartile and $Q_1$ as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: $\{59,76,84,93,95,97,101,101,102,102,104,106\}$

Next, find the median:

$\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99$

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

$\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5$

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

$\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102$