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andrezito [222]
3 years ago
12

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

d C, as shown below:
A source of laser light is at point A on the ground between two parallel walls. The walls are perpendicular to the ground. AB is a ray of light which strikes the wall on the left at point B. The length of AB is 60m.AC is a ray of light which strikes the wall on the right at point C which is 40m above the ground. The ray AB makes an angle of 60 degrees with the ground. The ray AC makes an angle of 45 degrees with the ground.

What is the distance between the walls?

the options are
80
140
70
110

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0
Well there is a lot of trigonometry in this. I will try my best.

Finding: Distance between Wall A and Wall B.

1. Trig and phythagorean properties for left triangle.
    30m

2. Trig and Pythagorean properties for right triangle.
     40m (approx)

30 + 40 = 70.

Therefore the distance is APPROXIMATELY 70 meters. I haven't learned trig yet so sorry if I am wrong.
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Given:

Consider the below figure attached with this question.

Angles of a triangle are x, y and z.

To find:

The values of x, y and z.

Solution:

If two angles are linear pair, then their sum is 180 degrees.

y+(3x+5)=180

y=180-3x-5

y=175-3x

Similarly,

z+(3x-5)=180

z=180-3x+5

z=185-3x

According the the angle sum property, the sum of all angles of a triangle is 180 degrees.

x+y+z=180

x+(175-3x)+(185-3x)=180

-5x+360=180

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Divide both sides by -5.

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The value of x is 36.

y=175-3(36)

y=175-(108)

y=67

Now,

z=185-3(36)

z=185-108

z=77

Therefore, the values of x, y and z are 36, 67 and 77 respectively.

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