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Pavel [41]
3 years ago
10

This should be easy its a trigonometry question in geometry

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0
Where are the questions at?
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Can 25/35 be simplified?
anygoal [31]
Yes. 25 and 35 both go into 5 so 25=5, 35=7.
So the answer is 5/7.
Hope this helps :)

3 0
4 years ago
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Find the lateral area of a cylinder
Dovator [93]

Answer:

314 cm^2

Step-by-step explanation:

(=^w^=)

A= 2*pi*r*h

A=2*pi*5*10

A=314.16 cm^2

7 0
3 years ago
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on the playground 1/4 kids are on the jingle gym and 1/3pm are playing kick ball.how many kids are on the jungle gym or playing
DaniilM [7]
1/12 kids are playing on the playground
3 0
3 years ago
Find the measure of the largest angle.
mihalych1998 [28]

Answer:

4x-7

Step-by-step explanation:

Solve for x:

180 = 44 + 3x - 11 + 4x - 7

Combine like terms: 180 = 26 + 7x

Simplify: 154 = 7x

Simplify: 22 = x

Substitute: 3(22) - 11 = 55 and 4(22) - 7 = 81

Create inequality: 44 < 55 < 81

8 0
3 years ago
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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
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