look ar the photo, x is 4
Answer:
8
Step-by-step explanation:
[-2][-2]=-2 x-2=4
4+4=8
<span>(x - y + 1) - (x + y - 1)
x - y + 1 - x - y + 1
= (x - x) + (y - y) + (1 + 1)
= -2y + 2
In short, Your Answer would be: -2y + 2
Hope this helps!</span>
Y = 1 + i
<span>(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i </span>
<span>(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i </span>
<span>1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i </span>
<span>1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i </span>
<span>-3 - 4i + k = -i </span>
<span>k = 4i - i + 3 </span>
<span>k = 3i + 3 </span>
<span>k = 3 * (1 + i) </span>
<span>k = 3y</span>
Answer:
B=23.19
Step-by-step explanation:
First, find the last side of the triangle using the Pythagorean theorem.
![a^{2} +b^{2} =c^{2} \\21^{2} +9^{2} =c^{2} \\441+81=c^{2} \\\sqrt[3]{58}=c](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C21%5E%7B2%7D%20%2B9%5E%7B2%7D%20%3Dc%5E%7B2%7D%20%5C%5C441%2B81%3Dc%5E%7B2%7D%20%5C%5C%5Csqrt%5B3%5D%7B58%7D%3Dc)
Then, find the missing angle, lets name it B.
The angle B can be found using the inverse sine function.
B=arcsin(opp/hyp)
![B=arcsin(\frac{9}{\sqrt[3]{58} } )\\B=23.19](https://tex.z-dn.net/?f=B%3Darcsin%28%5Cfrac%7B9%7D%7B%5Csqrt%5B3%5D%7B58%7D%20%7D%20%29%5C%5CB%3D23.19)
