Answer:
Area of a regular decagon with a perimeter of 60 ft. = 277 squared ft
Step-by-step explanation:
Decagon has 10 sides So 60/10 = 6 (each side = 6ft )
The sum of the interior angles of a decagon is 1 440 degrees.
There are 10 equal isosceles triangles of base angles 72 degrees in a decagon
Each isosceles triangle can subdivided into 2 right-angled triangles with height h and base length = (6/2) = 3 cm and base angle 72 degrees.
Height of right-angled triangle h = 3 tan 72 ft.
Area of 1 right-angled triangle = (1/2)(3)(3 tan 72) = 13.85 squared ft
Area of decagon = 20 right-angled triangles = 277 squared ft
The fourth option is correct. 1. Switch f(x) for y 2. Transfer -10 as a +10 to the left side of the equation. y + 10 = 2x. 3. Then last, divide both sides by 2 to leave the x alone of the right. Now you have x = 1/2y + 5. Now switch back the y and x so it becomes y = 1/2x + 5. Also, make the y an h(x) to finish up.
Answer:
L and O
Step-by-step explanation:
The first given equation is:
4y + 1 = x .......> equation I
The second given equation is:
2x = 5y .......> equation II
Substitute with equation I in equation II to get the value of y as follows:
2x = 5y
2(4y+1) = 5y
8y + 2 = 5y
8y - 5y = -2
3y = -2
y = -2/3
Substitute with the value of y in equation I to get the value of x as follows:
x = 4y + 1
x = 4(-2/3) + 1
x = -5/3
Based on the above calculations:
x = -5/3
y = -2/3