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2 years ago

Using the graph, determine the coordinates of the y-intercept of the parabola. TT help

Mathematics

1 answer:

Alex787 [66]2 years ago

4 0

By using the graph (see attachment), the coordinates of the y-intercept of the parabola is (0, 7).

<h3>What is a graph?</h3>

A graph can be defined as a type of chart that's commonly used to graphically represent data points on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

In Mathematics, the y-intercept of any graph (parabola) occurs at the point where the value of "x" is equal to zero (0).

By critically observing the graph (see attachment), the coordinates of the y-intercept of the parabola is given by:

y-intercept = (0, 7).

Read more on y-intercept here: brainly.com/question/19576596

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Answer:

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3 years ago

Find the area of the region that lies inside the first curve and outside the second curve.

marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = $\dfrac{1}{2}$

$\theta = -\dfrac{\pi}{3}, \ \ \dfrac{\pi}{3}$

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \ \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ 5^2 d \theta$

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \ \theta d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ d \theta$

$A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} \dfrac{cos \ 2 \theta +1}{2} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}$

$A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} {cos \ 2 \theta +1} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}} \ \ - \dfrac{25}{2} \begin {bmatrix} \dfrac{2 \pi}{3} \end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3}) \end {bmatrix} - \dfrac{25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} + \dfrac{\pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}$

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx

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3 years ago

Please help me real quick i need this question.

andrew11 [14]

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4 years ago

Help pleaseeee NO LINKSSSS

Rainbow [258]

Answer:

Step-by-step explanation:

Radius=r. Diameter=d. C=circumference. A=area

Starting from the center of the circle any line drawn to any point on the circumference of the circle is the radius, if the line is drawn from one point on the circumference to another point on the circumference through the centre of the circle that is the diameter. The circumference of the circle is the perimeter of the circle.

Formulas;

r=d÷2

C=2πr

A=πr²

π= $\frac{22}{7}$ or 3.142

4).

a.)r=d÷2

=4.8cm÷2

=2.4cm

b.)d=4.8cm

c.)C=2πr

=2×3.142×2.4cm

=15.08cm

d.) A=πr²

=3.142×(2.4)²

=3.142×5.76

=18.09cm² or 18.1cm²

a.)r=d÷2

=7÷2

=3.5cm

b.)d=7cm

c.)C=2πr

=2×3.142×3.5

=21.99cm or 21.1cm

d.)A=πr²

=3.142×(3.5)²

=3.142×12.25

=38.49cm²

6.)

a.)r=d÷2

=14÷2

=7cm

b.)d=14cm

c.)C=2πr

=2×3.142×7

=43.99cm

d.)A=πr²

=3.142×(7)²

=3.142×49

=153.96cm²

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3 years ago

Nationally, the proportion of red cars on the road is 0.12. A statistically

notka56 [123]

Answer:

Null hypothesis: proportion of red Phillies cars is 0.12.

Alternate hypothesis: proportion of red Phillies cars is not 0.12.

Step-by-step explanation:

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3 years ago