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andreyandreev [35.5K]
4 years ago
5

Find the average value of f over region

Mathematics
1 answer:
Sedaia [141]4 years ago
7 0

The average value of f(x,y) over the region \mathcal D is

\dfrac{\displaystyle\iint_{\mathcal D}f(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_{\mathcal D}\mathrm dx\,\mathrm dy

We can describe the region \mathcal D as the set

\{(x,y)\mid0\le x\le1,\,0\le y\le8x\}

So the integral in the numerator is

\displaystyle\iint_{\mathcal D}5xy\,\mathrm dx\,\mathrm dy=5\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=40

The integral in the denominator is the same as the area of \mathcal D, which is a right triangle, so it's easy to compute

\displaystyle\iint_{\mathcal D}\mathrm dx\,\mathrm dy=\frac12\cdot1\cdot8=4

So the average value is \dfrac{40}4=10.

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If f(x)f(x) is an exponential function where f(4.5)=23f(4.5)=23 and f(8)=42f(8)=42, then find the value of f(5.5)f(5.5), to the
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Step-by-step explanation:

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Help me on this please!
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If y=27 when x= 8 find y when x =11
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Step-by-step explanation:

The problem probably assumes direct variation

y=kx

IF so, then plug in the values and solve for k

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the problem is making some assumption about the relation between x and y.  The simplest assumption that's likely is direct variation,  that x and y are linearly related.  The graph is a straight line through the origin with slope = 27/8

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