Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.
Carl had .5 left of a snack bar.
Dave had .3 left of a snack bar.
Tony had .5 left of a snack bar.
Gary had .0 left of a snack bar.
Tryone had .7 left of a snack bar.
If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.
7 of them fish I’m not going to lye I just wanted to put 7 but I have to have at least 20 characters
Answer:
![\frac{11}{12} - \frac{1}{3} = \frac{7}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B7%7D%7B12%7D)
Step-by-step explanation:
Given
See attachment for question
Required
Solve
We have:
![\frac{11}{12} - \frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D%20-%20%5Cfrac%7B1%7D%7B3%7D)
Take LCM and solve
![\frac{11}{12} - \frac{1}{3} = \frac{11 - 4}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B11%20-%204%7D%7B12%7D)
![\frac{11}{12} - \frac{1}{3} = \frac{7}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B12%7D%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B7%7D%7B12%7D)
THis equals the number of permutations of 4 from 6.
= 6P4 = 6! / (6 - 4)! = 6! / 2! = 720/2 = 360 answer