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Otrada [13]
3 years ago
10

By comparing medians which person went to the movies the most per month

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

I think they all went to the movies equally per month if you simply compare medians? Since in the second chart, they each have a median of 2 times per month, that makes it equal. If you aren’t sure if this is correct, you have to order how many times each person went to the movies, from least to greatest. For example, John’s would be 1,1,1,2,2,2,2,3,3,3,4,5. Then you would start crossing numbers off from each end. First you would cross off 1, then 5, and then 1, and then 4, and keep going until you reach the number in the very middle, which is 2. Do this with all of the other people, and check if everybody has 2 for a median. I believe they do, however it’s always best to check and be safe. Good luck

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If your car gets 28 miles per​ gallon, how much does it cost to drive 390 miles when gasoline costs ​$2.90 per​ gallon?
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Answer: x = $25.89

Step-by-step explanation:

This is a two step problem.  First we need to determine the number of gallons the car uses to drive the 250 miles:

250/28 ≈ 8.93 gallons

Then we just multiply the number of gallons by the price:

8.93 x 2.90 = $25.90

Alternate solution:  Use a proportion.  Since 1 gallon costs $2.90 and produces 28 miles, we can set up the following proportion:

2.90/28 = x/250

Cross-multiply and solve:

28x = 725

x = $25.89 (There is a one cent difference due to a rounding error in the first solution.  This solution avoids that error.)

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Step-by-step explanation:

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Y_(1)=3(5x-9)-3,y_(2)=8(x-5)+15,y_(1)=y_(2)
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Step-by-step explanation:

6 0
1 year ago
A random sample of 300 circuits generated 13 defectives. Use the data to test the hypothesis Upper H Subscript 0 Baseline colon
____ [38]

Complete Question

A random sample of 300 circuits generated 13 defectives. a. Use the data to test

                            H_o : p = 0.05

Versus

 

                          H_1 : p \ne 0.05

Use α = 0.05. Find the P-value for the test

   

Answer:

The  p-value is  p-value =  0.5949        

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 300

    The number of defective circuits is  k = 13

Generally the sample proportion of defective circuits is mathematically represented as

        \^ p = \frac{k}{n}

=>     \^ p = \frac{13}{300}

=>     \^ p = 0.0433

Generally the standard Error is mathematically represented as

       SE  = \sqrt{\frac{p(1- p)}{n} }

=>     SE  = \sqrt{\frac{0.05(1- 0.05)}{300} }

=>     SE  = 0.0126

Generally the test statistics is mathematically represented as

       z =  \frac{\^ p - p }{SE}

=>     z =  \frac{0.0433 - 0.05 }{0.0126}

=>     z =  -0.5317

From the z table  the area under the normal curve to the left  corresponding to  -0.5317  is

         (P < -0.5317 ) = 0.29747

Generally the p-value is mathematically represented as

       p-value =  2 * P(Z <  -0.5317 )

=>     p-value =  2 * 0.29747

=>     p-value =  0.5949        

     

3 0
3 years ago
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