Answer:
All polynomials of the p=at² where a is in R is a subspace Pn for an appropriate value of n do not fulfill the condition and hence do not form the subspace
Step-by-step explanation:
Check attachment
For this case we have:
Let a function of the form
By definition, to graph , where , we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that
So, if the black graph is given by, the red graph is given by:
Answer:
Option A
The difference is 6 because it is what we get when we subtract 8 and 2.
Final answer: 6
Let
x-------> t<span>he horizontal length of the roller coaster
y------> </span>the elevation of the roller coaster
c------> t<span>he incline of a roller coaster
</span>
we know that
applying the Pythagoras theorem
c²=x²+y²-----> equation 1
c=2y-----> equation 2
x=11+y----> equation 3
substitute equation 2 and equation 3 in equation 1
[2y]²=(11+y)²+y²
4y²=11²+22y+y²+y²
2y²-22y-121=0
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
y=15.026 m
c=2*y-----> c=2*15.026----> c=30.052 m
the answer is30.05 m