Answer:
0.066
Step-by-step explanation:
We solve this question using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation
For the question
mean birth weight for boys is 3.27 kg, with a standard deviation of 0.51 kg.
x = 2.5
Hence:
z = 2.5 - 3.27/0.51
z = -1.5098
Probability value from Z-Table:
P(x ≤ 2.5) =P(x < 2.5) = P(x = 2.5) =
=0.065547
Therefore, the proportion of baby boys that are born with a low birth weight is 0.066
280,706 is the standard form
Answer:
The correct answer is first option
u² - 11u + 24 = 0
When u = (x² - 1)
Step-by-step explanation:
It is given that,
(x² - 1)² - (x² - 1) + 24 = 0
<u>To find the correct answer</u>
Substitute u = x² - 1
The equation becomes,
u² - 11u + 24 = 0 Where u = (x² - 1)
Therefore the correct answer is first option
u² - 11u + 24 = 0
When u = (x² - 1)
Answer:
b. There is a 95% chance that the true proportion of teenagers who use Mybook as their primary social network site is in the interval (0.2964, 0.9036).
Step-by-step explanation:
Hello!
In general, a 95% confidence interval for the population proportion can be interpreted as: There is a 95% chance (or confidence) that the interval will contain the true value of the proportion.
(Remember the confidence level of 95% means that if you were to make 100 intervals for the population proportion, 95 of them will contain its true value)
The estimated parameter is the population proportion of teenagers that use Mybook as their primary social network site.
With this in mind then you can say that there is a 95% probability that the interval (0.2964, 0.9036) will contain the true value of the proportion of teenagers that use Mybook as their primary social network site.
The correct answer is: b
I hope this helps!
