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2 years ago

13

Helpppp meeeeeee asssapppp noooo rockyyyyyy

1 answer:

Mamont248 [21]2 years ago

4 0

Answer:

12

Step-by-step explanation:

4y - 2x

= 4(7) - 2(8)

= 28 - 16

= 12

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Find the value of x in the triangle shown below 3.5 4 3.5 x• 55•

Dvinal [7]

Answer:

Step-by-step explanation:

Since this is not a right triangle, we will use the Law of Sines. For us that looks like this:

$\frac{sin55}{3.5} =\frac{sinx}{4}$ and cross multiply to get

4sin55 = 3.5sinx and solve for sinx:

$sinx=\frac{4sin55}{3.5}$ so

sinx = .9361737 Use the 2nd button on your calculator and the sin button to find that the angle

x = 69.4°. Not sure how you need it rounded. It's actually 69.4186°

6 0

2 years ago

A meteorologist reported that in the month of April there were 3 inches more rainfall than normal. Write an integer to represent

BartSMP [9]

Answer:

3

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Tom jogged 3/5 mile on Monday and 2/6 mile on Tuesday how much farther did Tom joy on Monday then on Tuesday

gogolik [260]

$\bf \cfrac{3}{5}-\cfrac{2}{6}\impliedby \textit{so, we'll use an LCD of 30}\implies \cfrac{(6\cdot 3)-(5\cdot 2)}{30}
\\\\\\
\cfrac{18-10}{20}\implies \cfrac{8}{20}\implies \cfrac{2}{5}$

3 0

3 years ago

The drawing of the building, shown below, has a scale of 1 inch to 30 feet. What is the actual height, in feet, of the building?

andreyandreev [35.5K]

Answer:

Actual height of the building is 37.5 feet

Step-by-step explanation:

Formula to be used to get the actual length of the building,

Scale used = $\frac{\text{Dimension of image (on map)}}{\text{Dimension of actual}}$ = $\frac{1}{30}$

By this formula,

$\frac{1.25}{\text{Actual height}}=\frac{1}{30}$

Actual height of the building = 1.25 × 30

= 37.5 feet

Therefore, actual height of the building will be 37.5 feet.

6 0

2 years ago

If line segment BC is considered the base of triangle ABC, what is the corresponding height of the triangle?

Leni [432]

Answer:

1.6 units

Step-by-step explanation:

Coordinates of A : (-1,1)

Coordinates of B : (3,2)

Coordinates of C :( -1,-1)

Now to find the length of the sides of the triangle we will use distance formula :

$d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

To find length of AB

A = $(x_1,y_1)=(-1,1)$

B= $(x_2,y_2)=(3,2)$

Now substitute the values in the formula:

$d =\sqrt{(3-(-1))^2+(2-1)^2}$

$d =\sqrt{(4)^2+(1)^2}$

$d =\sqrt{16+1}$

$d =\sqrt{17}$

$d =4.12$

Now to find length of BC

B= $(x_1,y_1)=(3,2)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-3)^2+(-1-2)^2}$

$d =\sqrt{(-4)^2+(-3)^2}$

$d =\sqrt{16+9}$

$d =\sqrt{25}$

$d =5$

Now to find length of AC

A = $(x_1,y_1)=(-1,1)$

C = $(x_2,y_2)=(-1,-1)$

Now substitute the values in the formula:

$d =\sqrt{(-1-(-1))^2+(-1-1)^2}$

$d =\sqrt{(0)^2+(-2)^2}$

$d =\sqrt{4}$

$d =2$

Thus the sides of triangle are of length 4.12, 5 and 2

Now to find area of triangle we will use heron's formula :

To calculate the area of given triangle we will use the heron's formula :

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

Where $s = \frac{a+b+c}{2}$

a,b,c are the side lengths of triangle

a = 4.12

b=5

c=2

Substitute the values

Now substitute the values :

$s = \frac{4.12+5+2}{2}$

$s =5.56$

$Area = \sqrt{5.56(5.56-4.12)(5.56-5)(5.56-2)}$

$Area = 3.99$

Now to find the height of altitude corresponding to side BC

So, formula of area of triangle $=\frac{1}{2} \times Base \times Height$

Since Area = 3.99 square units

So, $3.99 =\frac{1}{2} \times BC \times Height$

So, $3.99 =\frac{1}{2} \times 5\times Height$

$3.99 =2.5 \times Height$

$\frac{3.99}{2.5}=Height$

$1.596=Height$

Thus the altitude corresponding to the BC is of length 1.596 unit ≈ 1.6 units

Thus Option D is correct.

7 0

2 years ago

Read 2 more answers