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IgorC [24]
3 years ago
9

Four years after opening an account that paid simple interest of 4.25% annually, a depositor withdrew the $2,380 in interest ear

ned. How much money was left in the account? $
Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula

prt = I, where

p is the initial investement,

r is the interest rate in decimal form,

t is the time in years, and

I is the interest earned. Notice that we have all those things but the p.

Filling in:

p(.0425)(4) = 2380 and

.17p = 2380 so

p = 14000

That means that 14000 was initially invested. If the depositor withdrew the 2380, then

14000 - 2380 is the amount left in the account, namely, $11620

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In a recent poll, 700 people were surveyed. 77% of them said they opposed the current war. How many people stated they were in o
MrRa [10]

Answer:

539

Step-by-step explanation:


6 0
2 years ago
Given vectors A (2,-1,5), B (4,3,-2) & C (5,4,0), find:?
MrRissso [65]
A) 4a - 3b + 2c

4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =

= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)

Answer: (6, - 5, 26)

b) magnitude of vector b

\sqrt{4^2+3^2+(-2)^2} = \sqrt{16+9+4} = \sqrt{29} ~ 5.4

c) vector of length 7 parallel to vector c

=> m(5,4,0) = (5m,4m,0)

=>    \sqrt{(5m)^2+(4m)^2+0}= \sqrt{25m^2+16m^2}= \sqrt{41m^2}=m \sqrt{41}=7

=> m = 7 / √41 ≈ 1.093

=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)

Answer: (5.465 , 4.372 , 0)
7 0
3 years ago
Solve the following equation: <br>(n + 1) + 3(n - 1) = 2(n - 1)(n + 1)​
Mnenie [13.5K]

Answer:

n = 0, n =2

Step-by-step explanation:

Given

(n + 1) + 3(n - 1) = 2(n - 1)(n + 1) ← distribute parenthesis on both sides

n + 1 + 3n - 3 = 2(n² - 1), that is

4n - 2 = 2n² - 2 ( subtract 4n - 2 from both sides )

0 = 2n² - 4n ← factor out 2n from each term )

0 = 2n(n - 2)

Equate each factor to zero and solve for n

2n = 0 ⇒ n = 0

n - 2 = 0 ⇒ n = 2

7 0
3 years ago
Carissa counts by 5s from 32 to 62. Which number does carissa count?
polet [3.4K]

Answer:

32, 37, 42, 47, 52, 57, 62.

Step-by-step explanation:

It is given that Carissa counts by 5s from 32 to 62.

It means, we have to add 5 in the number to get the next number.

Add 5 in 32.

32+5=37

Now, add 5 in 37.

37+5=42

Similarly, continue the process.

42+5=47

47+5=52

52+5=57

57+5=62

Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.

8 0
3 years ago
1. A costume designer made 10 costumes that each used 5.8 yards of fabric. If she had 238.2 yards of fabric to start with, about
Zinaida [17]
 <span>You only need an estimate? Great. Think of the necessary material as 6 yards, so ten costumes would take 60 yards. Then think of the fabric on hand as 240 yards, so taking 60 yards away from that would leave [an estimated] 180 yards of fabric. 

For an equation, use: 

F" = F' - 5.8 C 

Where F' is the initial fabric stock, F" is the remaining fabric, and C is the count of costumes. 

In exact numbers, the formula works out to: 

F" = 238.2 - (5.8 * 10) 

F" = 180.2 

The estimate was very close. 

Good luck.</span>
4 0
3 years ago
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