Answer:2/1
Step-by-step explanation:
Answer:
You can't get a square root of any number that has a negative sign on the inside of the radical
Answer:
p=4x^3−3x^2+5x−2/x
Step-by-step explanation:
Let's solve for p.
px=4x^3−3x^2+5x−2
Step 1: Divide both sides by x.
px/x=4x^3−3x^2+5x−2/x
p=4x^3−3x^2+5x−2/x
Answer:
p=4x^3−3x^2+5x−2/x
( I hope this was helpful) >;D
Answer:
Step-by-step explanation:
2x^2-6x+10=0
2(x^2-3x)+10=0
2(x-(3/2))^2-9/4)+10=0
2(x-(3/2))^2+10-9/2=0
2(x-(3/2))^2+(20-9)/2=0
2(x-(3/2))^2+11/2=0
2(x-(3/2))^2=-11/2
square is always positive so there is no solution
