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n200080 [17]
3 years ago
6

Find the equation of the line Which passes through ( -4,-2) and it is parallel to 2y-6x-3 =0

Mathematics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

y = 3x + 10

Step-by-step explanation:

In this question, we have to find an equation of a line that's parallel to the equation given.

First, lets turn the given equation into slope-intercept form:

2y - 6x - 3 = 0

Add 6x and 3 to both sides.

2y = 6x + 3

Divide both sides by 2.

y = 3x + 3/2

We know that the slope of our parallel line has to be 3, now we just need to find what our beginning point, or y-intercept, is.

To find our parallel line, plug in the coordinates to the y = 3x + b and solve.

Solve for b:

-2 = 3(-4) + b

-2 = -12 + b

Add 12 to both sides.

10 = b

Our parallel equation would be: y = 3x + 10

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Hey!
The formula of direct variation is y = kx. So we know that p = kr^2
Hint: after it says varies, it's basically the equal sign. 
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