Question

An HR director numbered employees 1 through 50 for an extra vacation day contest. What is the probability that the HR director will select an employee who is not a multiple of 13?
Give your answer as a fraction.​

Answer 1

Answer:

The probability that the HR director will select an employee who is not a multiple of 13 is $\frac{47}{50}$

Step-by-step explanation:

* Lets explain how to solve the problem

- The probability of an event is the measure of the chance that the

  event will occur

- The probability of an event A is the number of ways that event A can

 occur divided by the total number of possible outcomes

- If P(A) is the probability of event A,  is the probability that the event A

 does not occur is 1 - P(A)

* Lets solve the problem

- An HR director numbered employees 1 through 50 for an extra

 vacation day contest

∴ There are 50 employees

- The HR director will select an employee

- We need to find the probability of select an employees who is not

 multiple of 13

* At first lets find the multiples of 13

∵ 13 × 1 = 13

∵ 13 × 2 = 26

∵ 13 × 3 = 39

∴ The multiples of 13 from 1 to 50 are 13 , 26 , 39

∵ There are 3 multiples of 13

∵ There are 50 numbers

∵ Probability of multiple of 13 = $\frac{3}{50}$

∵ Probability of not multiple of 13 = 1 - P(multiple of 13)

∴ Probability of not multiple of 13 = $1-\frac{3}{50}$

∴ Probability of not multiple of 13 = $\frac{47}{50}$

* The probability that the HR director will select an employee who is

  not a multiple of 13 is $\frac{47}{50}$