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kap26 [50]
3 years ago
6

Jamie has 8/10 of a candy bar leftover. He wants to split it into 1/3 pieces. How many 1/3 pieces. How many 1/3 pieces can he ma

ke
Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0
If we change everything to the same denominator it will look like this. 24/30 and he wants to take 10/30. 24/30 - 10/30 is 14/30 so 14/30 - 10/30 is 4/30. *He can take 2 1/3 pieces*
dedylja [7]3 years ago
6 0
Jamie has 8/10 of a candy bar, and wants to split it into an unknown number of 1/3 pieces. Our objective is to find the number of pieces.
Let the number of pieces be x.
To know the portion of the candy bar each piece is, we divide the total portion of the candy bar by the number of pieces.
So (8/10)/x = 1/3
Multiply each side by x
8/10 = 1/3x
Divide each side by 1/3 so we can have the variable x on a side, and its value on another.
(8/10)/(1/3) = (1/3x)/(1/3)
(8/10) / (1/3) = x
Dividing 2 fractions is equal to multiplying the first fraction by the inverse of the second:
(8/10) / (1/3) = x
(8/10) * 3 = x
24/10 = x
x = 2.4

Since this not a whole number, Jamie can make 2 full 1/3 pieces, and a piece of 1/10.
Or, you can easily say that Jamie can make 2.4 pieces of 1/3.

Hope this Helps! :)
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3 years ago
Question 4 A triangle has two sides that are 8 cm and 13 cm. What could be the length of the triangle's third side? Select three
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know what is the third side length

the difference between the 2 other sides <  the greatest side of triangle < the sum of 2 other sides

so here the answers here could be ( 10- 17 - 20)

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4 0
3 years ago
mr. parra brought a coffee to school this morning. after first period, he only had 15% of the coffee left. if he had 210 mL of c
maksim [4K]

Answer:

Step-by-step explanation:

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60 / 4 = 15

Now we divide their total of $210 by their hourly rate of $15 to find how many hours it would take.

210 / 15 = 14

I would take 14 hours to earn $210.  

<u>If im right brainliest plz </u>

Hope this helps :)

3 0
3 years ago
Read 2 more answers
HeLp MeEeE!!! (25pts)<br>do them all please
Paul [167]
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