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Anni [7]
3 years ago
9

How many years will it take to double an investment at 11% simple interest? ​

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

10 years

Step-by-step explanation:

We can use the equation for simple interest: <em>I = P(1 + (R*T))</em>, and change some of the numbers: <em>2P = P(1 + (0.11*T))</em>

Divide: <em>2 = 1 + (0.11*T)</em>

Subtract: <em>1 = 0.11*T</em>

Divide: <em>T = 100/11 ≈ 9.09</em> ⇒ 10 years (rounded up because it won't be doubled until the next year)

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Answer:

The quotient is : x+9

The remainder is : 13

Step-by-step explanation:

The question requires you to perform the long division method;

This will be;

x-2\sqrt{x^2+7x-5}

start with the x term in x-2 and the first term in the function, x², to get x then multiply the x with x-2 to get x²-2x and perform the operation below;

x-2√x²+7x-5 -----------to first get x and then multiply x*[x-2]⇒x²-2x

    -  x²-2x+0 ------------perform subtraction of like terms

---------------------

            9x-5  ----now divide this answer by x-2 ,starting with x and 9x

----------------------This will give , 9 then multiply  9 by x-2 to get 9x-18 and perform the subtraction operation as;

             9x-5

      -      9x-18

------------------------

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So the answer will be; x+9 remainder 13

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