How many years will it take to double an investment at 11% simple interest?

Mathematics

1 answer:

ddd [48]3 years ago

7 0

Answer:

10 years

Step-by-step explanation:

We can use the equation for simple interest: I = P(1 + (R*T)), and change some of the numbers: 2P = P(1 + (0.11*T))

Divide: 2 = 1 + (0.11*T)

Subtract: 1 = 0.11*T

Divide: T = 100/11 ≈ 9.09 ⇒ 10 years (rounded up because it won't be doubled until the next year)

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PLEASE HELP!

Orlov [11]

We have that
If (5x-4+13x=5) --------------> then x=1/2
Step 1
let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then
5=5-----------> the value of x = (1/2) satisfies equality

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3 years ago

Add and simplify 1/5 + 1/10

aliya0001 [1]

In order to add these fractions we have to make a common denominator.

1/5 can turn into 2/10 Its the same thing. And its easier to solve with.

now lets multiply.

$\frac{2}{10}$ × $\frac{1}{10}$

Now we add across

2 + 1 = 3

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10 + 10 = 10 ( When adding fractions like these the denominator stays the same)

So your answer is...

$\frac{3}{10}$

Good Luck! :)

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3 years ago

What is the slope intercept form of the equation of 6x+5y=-15

Soloha48 [4]

Slope intercept form is $\sf y=mx+b$ , where 'm' is the slope and 'b' is the y-intercept.

$\sf 6x+5y=-15$

Subtract 6x to both sides:

$\sf 5y=-6x-15$

Divide 5 to both sides:

$\boxed{\sf y=-\dfrac{6}{5}x-3}$