The sum of the first eight terms of the geometric sequence whose first term is -2.5 and ratio is 2 is: -637.5
The nth term of a geometric sequence is given mathematically as;
T(n) = ar^n
- where, a = first term of the geometric sequence.
- r = common ratio of the sequence
- and n = nth term of the sequence.
Therefore, the sum of the first 8 terms of the geometric sequence is;
- <em>S(8) = a + ar + ar² + ar³ + ar⁴ + ar⁵ + ar⁶ + ar⁷.</em>
In essence;
- since common ratio, r = 2
Therefore, we have;
- S(8) = -2.5(1 + 2 + 2² + 2³ + 2⁴ + 2⁵ + 2⁶ + 2⁷)
S(8) = -637.5.
Therefore, the sum of the first eight terms of the <em>geometric sequence</em> whose first term is -2.5 and ratio is 2 is: -637.5
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brainly.com/question/22673892
Answer:
16
Step-by-step explanation:
4^2
This means the base of 4 multiply by itself 2 times
4*4
16
Answer:
It's the last choice.
Step-by-step explanation:
1. (3x - 2y)(3x -2y)
= 9x^2 - 12xy + 4y^2
The product is (9x^2 - 4y^2) (9x^2 - 12xy + 4y^2)
which is neither a difference of 2 squares or perfect square trinomial.
2. (3x - 2y)(3x + 2y)
= 9x^2 - 6xy + 6xy - 4y^2
= 9x^2 - 4y^2
and (9x^2 - 4y^2(9x^2 - 4y^2) is a perfect square.
26 cm/s equals >15.6 m/min
18 1/4 pieces she will have now
:)
