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nignag [31]
2 years ago
8

At a school fair you have a choice of randomly picking a ball from Basket A or Basket B. Basket A has 5 green balls, 3 red balls

, and 8 yellow balls. Basket B has 7 green balls, 4 red balls,and 9 yellow balls. You can win a digital book reader if you pick a red ball
1.Which basket should you choose if you want the better chance of winning?
Mathematics
2 answers:
Dafna11 [192]2 years ago
7 0

Answer:

<u>Basket A</u>      <u>Basket B</u>

  16                   20

   3                     4

3/16                  1/5

           Basket B

Karolina [17]2 years ago
6 0
Basket A is 3/16 red.
Basket B is 3/15 red.
The answer is Basket B.
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Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
Add and reduce to lowest terms: 5 1/4+4 5/6
lakkis [162]

Answer:

−6.7 + (−2 1/ 5 )

Step-by-step explanation:

−6.7 + (−2 1/ 5 )

4 0
2 years ago
Read 2 more answers
2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.
kompoz [17]
74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
16=x
So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
y=26+2(16)
y=26+32
y=58.
So to check our answer we can plug in both values into the beginning equation.
74=58+16
74=74.
So to sum this up the smaller number is 16 and the larger number is 58.

4 0
3 years ago
A rain gutter along the edge of a roof has the shape of a rectangular prism. It is 11 inches ​high, 2 inches ​wide, and 11 feet
Rus_ich [418]

Answer:

hi love u

Step-by-step explanation:

wanna talk its bruce

6 0
2 years ago
Martina turns on a treadmill to start walking.
SpyIntel [72]

Answer:

Step-by-step explanation:

it is number 1

5 0
2 years ago
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