Answer:
arc AB = 70°
arc BC = 110°
arc ABC = 180°
arc CDB = 250°
Step-by-step explanation:
Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.
Solve for arc AB:
Angle AFB = 70°, so arc AB = 70°
Solve for arc BC:
Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.
180 - 70 = 110°
Since angle BFC = 110°, arc BC = 110°
Solve for arc ABC:
Add arc AB and arc BC together.
70° + 110° = 180°
arc ABC = 180°
Solve for arc CDB:
There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.
360° - 110° = 250°
arc CDB = 250°
Answer:
the equation is : x²-x-12
Step-by-step explanation:
the quadratic equation is in the form of : y=ax²+bx+c
the product of the zeros is -12 and the sum is 1
b = - 1
c=-12 (product)
y=x²-x-12
check : factorize first (x+3)(x-4)=0
either x+3=0 then x=-3
or x-4=0 then x=4
-3*4=-12
-3+4=1
the equation is : x²-x-12
