Explanation : Δ of ax^2 +bx +c is b^2 -4ac And if the Δ =0 then, we have one real root And if Δ > 0 then the roots are real and distinct And if Δ < 0 then there are no real roots
In above equation a =8, b = 8 and c = 2 Apply the discriminant now, b^2 -4ac (8)^2-(4)(8)(2) 64 - 64 =0
Here, the Δ = 0 So this equation has one solutions.
[Note: Δ is the symbol used to represent discriminant]
as the discriminant is 0, one solution will be -b/2a = -1/2
But still, we can't say that it has only one solution due to the nature of quadratic equations(It's tendency to have two solutions). But we can say that both solutions are coincident.