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2 years ago

Solve. Use the strategy "work backward."

Mathematics

1 answer:

cestrela7 [59]2 years ago

8 0

Let that be x

ATQ

$\\ \rm\Rrightarrow 3x-6/5=9$

Arrange accordingly to work backwards(Every thing is reversed)

$\\ \rm\Rrightarrow 9(5)+6/3=x$

$\\ \rm\Rrightarrow 45+6/3=x$

$\\ \rm\Rrightarrow 51/3=x$

$\\ \rm\Rrightarrow x=17$

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Do the ratios 20:18 and 3:2 form a proportion?

DENIUS [597]

Answer:

No.

Step-by-step explanation:

When trying to make this into a proportion, the left and right sides of the equation are unequal, therefore this is invalid.

#learnwithbrainly

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3 years ago

Read 2 more answers

Write an algebraic expression for the perimeter of the swimming pool

Pachacha [2.7K]

Answer: I don't see that you have a diagram of the swimming pool or any given side measures but assuming it is a rectangle, the algebraic expression would be 2(L+W) where L is the length and W is the width.

Step-by-Step Explanation: So when you are finding the perimeter, you are finding the length of the space surrounding something. So you would add up the length of all its sides to find it. In a rectangle, opposite sides are equal, therefore the length will be equal to the side opposite to it and the width will also be equal to the side opposite to it. So if you were to write the expression like that, you would get L+L+W+W, which can be simplified to 2L+2W, or just 2(L+W).

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3 years ago

The base of a hexagonal prism has an area of 96 square inches. The height of the prism is 9 inches. Find the volume of the prism

Kitty [74]

Answer:

The volume of the prism is 864 inches^3.

Step-by-step explanation:

The basic formula for the volume of a prism is:

V = Ah

where:

V = Volume of prism

A = Area of uniform cross-section or base of prism = 96 inches^2

h = Perpendicular height of prism = 9 inches

Substitute the values given in the question into the formula.

V = 96 × 9

V = 864 inches^3

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3 years ago

Find the value of r 4(x-3)-r+2x=5(3x-7)-9x

vlabodo [156]

r = 4(x-3)/5(3x-7) + 11x

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3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

Let $\mu$ = true mean transmission of pages.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 10 pages {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, $H_A$ : $\mu$ > 10 pages {means that the true mean is greater than 10}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 14.44 pages

s = sample standard deviation = 4.45 pages

n = sample of fax transmissions = 35

So, test statistics = $\frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$ ~ $t_3_4$

= 5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_3_4$ > 5.9028) = Less than 0.05% {using t table)

7 0

3 years ago