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Delicious77 [7]
2 years ago
13

Solve. Use the strategy "work backward."

Mathematics
1 answer:
cestrela7 [59]2 years ago
8 0

Let that be x

ATQ

\\ \rm\Rrightarrow 3x-6/5=9

Arrange accordingly to work backwards(Every thing is reversed)

\\ \rm\Rrightarrow 9(5)+6/3=x

\\ \rm\Rrightarrow 45+6/3=x

\\ \rm\Rrightarrow 51/3=x

\\ \rm\Rrightarrow x=17

.

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saul85 [17]
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5 0
3 years ago
PLEASE ANSWER AS QUICK AS POSSIBLE
Lady_Fox [76]

Answer:

  (a)  h^-1(x) = (x+6)/6

Step-by-step explanation:

The inverse relation can be found by solving for y: x = h(y).

<h3>Solution</h3>

  x = h(y) . . . . . the inverse relation

  x = 6y -6 . . . . . use the function definition

  x +6 = 6y . . . . add 6

  (x +6)/6 = y . . . . divide by 6

The inverse function is ...

  \boxed{h^{-1}(x)=\dfrac{x+6}{6}}

4 0
2 years ago
Find the length and width of the frame
ahrayia [7]

Answer:

The width is - 4 the lengeth is - 7

Step-by-step explanation:

w*l = 28in²

w = ?

l = w+3

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2+3 = 5

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w = 3

3+3 = 6

6*3 = 18

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4+3 = 7

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W = 4 L = 7

6 0
3 years ago
What is the focus of the parabola<br> (y-3)^2=8(x-5)?
tino4ka555 [31]
Hello,

Let's suppose y'=y-3
and x'=x-5
Parabola  become y'²=8x' whose focus is (8/4,0)=(2,0)

y=y'+3==>y=0+3=3
x=x'+5==>x=2+5=7
Focus is (7,3)
Rem for parabola y²=kx focus is (k/4,0)


7 0
3 years ago
Help out a bab please?
aev [14]

Answer:

7

Step-by-step explanation:

4 0
3 years ago
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