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kati45 [8]
4 years ago
6

A man stores 72 liters of oil in 5 small cans and 2 large cans. If each large can hold twice as much as each small can, how many

liters does each can hold?
Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
3 0

Answer:

Small: 8

Large: 16

Step-by-step explanation:

If you know that each large can is twice the size of a small can then you can form the equation x=2x meaning every one large can equals two small cans. That means that the 2 large cans are equal to four small cans, so altogether you have nine small cans. Between those nine you have 72 liters, so your equation should be 72=9x. To solve you do 72/9 which is 8. That means eight liters are in a small can and you can double it to find that sixteen liters are in a big can.

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the product of a number X and 6 is 4 more than the product of the number and 3/8 which answer represents the situation
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6x=4+3/8x

That will be the answer

4 0
3 years ago
Help pleasee<br> On khan academy under geometry unit test.
Rzqust [24]
X=147
Angle x and 33 are a linear pair meaning they equal 180 and 180-33=147
5 0
3 years ago
Read 2 more answers
A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!
Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = \sqrt{44} units

Length of hypotenuse of triangle = 12 units

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Exact value of Cos A

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The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

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Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0
3 years ago
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