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3 years ago

What is the rate of change between (1,15) (3,45)?

Mathematics

1 answer:

Ksivusya [100]3 years ago

3 0

Answer:

Step-by-step explanation:

Rate of change or slope or gradient of a line passes two points (x1, y1) and (x2, y2) could be calculated by:

(y2 - y1)/(x2 - x1)

=> Rate of change of the line passing (1,15) and (3,45):

(45 - 15)/(3 - 1) = 30/2 = 15

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What pair of points have a slope of -3/5

sergey [27]

Answer:

(5,0) and (0,3) have a slope of -3/5

Step-by-step explanation:

Here, we want to state a pair of points that have a slope of -3/5

Mathematically, we can have the slope of a straight line calculated as;

m = y2-y1/(x2-x1)

This could give points like (5,0) and (0,3)

3 0

2 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

3 years ago

Write the percent as a fraction or mixed number in simplest form.<br> 12%

Anettt [7]

In order to convert percentage form into fraction, divide it by 100

So, 12% = 12/100 = 6/50 = 3/25

In short, Your Answer would be: 3/25

Hope this helps!

7 0

3 years ago

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Slove step-by-step (5+4)×2+6-(2×2)-1

Sladkaya [172]

1. (5 + 4) x 2 + 6 - (2 x 2) - 1
2. 9 x 2 + 6 - 4 - 1
3. 18 + 6 - 4 - 1
4. 24 - 4 - 1
5. 20 - 1
6. 19

3 0

3 years ago

{y | y E the set of integers and y> -7}

Ronch [10]

Can you upload a picture please

3 0

3 years ago

Read 2 more answers