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iogann1982 [59]
3 years ago
10

7. A square is altered so that one dimension is increased by 5 inches and the

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

Step-by-step explanation:

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.4^3Grafting, the uniting of the stem of one plant with the stem or root of another, is widely used commercially to grow the ste
11111nata11111 [884]

Answer:

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and conditional probability.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: No failed grafts in the first seven

Event B: At least one fail in the next three.

Intersection of events A and B:

Since the probability of a graft failling is independent of other grafts, we have that:

P(A \cap B) = P(A)*P(B)

So

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{P(A)*P(B)}{P(A)} = P(B)

So we just have to find the probability of one fail in three trials.

Three trials means that n = 3.

The probability is

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.4)^{0}.(0.6)^{3} = 0.216

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.216 = 0.784

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

3 0
3 years ago
The order in which you perform operations in a numerical expression does not matter
Rama09 [41]

<u>Answer:</u>

False

<u>Step-by-step explanation:</u>

The given statement: 'the order in which you perform operations in a numerical expression does not matter' is absolutely false.

The order or sequence in which a mathematical expression is solved does matter a lot. Performing mathematical operations in a different manner will result in different results.

The rule for performing mathematical operation states that a numerical expression should be solved in the following manner:

1. Brackets

2. Of

3. Division

4. Multiplication

5. Addition

6. Subtraction

5 0
4 years ago
4 1/15 divided by 3.1 PLEASE HELP
Elza [17]

Answer:

1.31182795699

Step-by-step explanation:

7 0
3 years ago
Victoria has 1/5 meter of string. She cuts it into 3 equal pieces. What fraction of a meter is each piece of string?
vredina [299]
Just do 1/5 divide by 3
4 0
3 years ago
A business owner bought a product for $20. The business owner sold the product for $35. By what percent was the product marked u
Salsk061 [2.6K]

Answer 7?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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