I don't how I would do this exactly..

A water tanker can fill

VikaD [51]

Answer:

56 mins

Step-by-step explanation:

Number of gallons of water in the pool per minute;

750 divided by 35 = 150/7

Let the time needed to fill a 1,200 gallon pool be t.

t x 150/7 = 1,200

t x 21.42857142857143... = 1,200

t = 1,200/21.42857142857143

t = 56 mins

6 0

3 years ago

GIVING BRAINLIEST!!! A student observes a beaker of room temperature water resting on a table. She states that the beaker of wat

attashe74 [19]

Answer:

b

Step-by-step explanation:

8 0

3 years ago

Irene has 1 gallon of milk. She uses

Umnica [9.8K]

Answer:

32

Step-by-step explanation:

In 1 gallon, there are 128 ounces.

Divide 128 by 4 and get 32.

5 0

2 years ago

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$