let's notice the tickmarks on the left and right sides, meaning those two sides are twins, and therefore equal, so the perimeter is simply 2.5+2.5+3.5+2.5 = 11 ft.
the trapezoid has an altitude/height of 2 ft, thus
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=2.5\\ b=3.5\\ h=2 \end{cases}\implies A=\cfrac{2(2.5+3.5)}{2}\implies A=6](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2.5%5C%5C%20b%3D3.5%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B2%282.5%2B3.5%29%7D%7B2%7D%5Cimplies%20A%3D6)
Answer:
First write them in positive exponent form
(16/81)¾ × [ (9/25)^3/2 ÷ (2/5)³ ]
(2⁴×¾)/ (3⁴×¾) × [ (3² × ^3/2) / (5² ×^3/2) ÷ 2³/5³)
Simplify the terms
2³/3³ × ( 3³ / 5³ ÷ 2³/5³)
Solve the terms in the bracket
2³/3³ × (3³/5³×5³/2³)
You will get
2³/3³ × 3³/2³ = 1
They will cancel each other so the answer will be 1
Hope this helps.
I believe you are asking for the area of the statue base.
r^2x3.14 = area of a circle
8 x 8 = 64
64 x 3.14 = 200.96
200.96 rounded = 201
The area of the statue base is 201 square feet.
