Answer:
The Y intercept is -5 and the slope is -5/2
first off, let's notice that Purple's time is in minutes, whilst the rate is in miles per hour, the units of both must correspond, so, we can either change the time from minutes to hours or the rate from hours to minutes, hmmm let's change the time to hours.
so 40 minutes, we know there are 60 minutes in 1 hour, so 40 minutes will be 40/60 of an hr, or namely 2/3.
![\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cqquad%20%5Cqquad%20%5Ctextit%7Binverse%20proportional%20variation%7D%20%5C%5C%5C%5C%20%5Ctextit%7B%5Cunderline%7By%7D%20varies%20inversely%20with%20%5Cunderline%7Bx%7D%7D%20~%5Chspace%7B6em%7D%20%5Cstackrel%7B%5Ctextit%7Bconstant%20of%20variation%7D%7D%7By%3D%5Ccfrac%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bk%7D%7D%7Bx%7D~%5Chfill%20%7D%20%5C%5C%5C%5C%20%5Ctextit%7B%5Cunderline%7Bx%7D%20varies%20inversely%20with%20%7D%5Cunderline%7Bz%5E5%7D%20~%5Chspace%7B5.5em%7D%20%5Cstackrel%7B%5Ctextit%7Bconstant%20of%20variation%7D%7D%7Bx%3D%5Ccfrac%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bk%7D%7D%7Bz%5E5%7D~%5Chfill%20%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer the statistical measures and create a box and whiskers plot for the following set of data. 4,4,5,5, 6, 6, 8, 10, 11, 11,
vredina [299]
Answer:
Step-by-step explanation:
First you take your smallest number, which in this case is 4 - then you find your maximum number which is 14. Then we can list these numbers on a piece of paper and cross a number out from each side until you reach the middle number which would be 8. Then you go from the min to the middle number which would be 5. Then you repeat between the max number and the middle number which is 11. So your minumum would be 4, max would be 14, Q1 would be 5 Median would be 8 and Q3 would be 11. Let me know if I got it right! I haven't done it for a while, but I am pretty sure this is correct..
(2xA)-3 is the answer because you multiply first than subtract so you put what you have to do first in parentheses like Pemdas