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erma4kov [3.2K]
4 years ago
12

15% of $9 is $____________

Mathematics
2 answers:
Sever21 [200]4 years ago
5 0

Answer:$1.35

Step-by-step explanation:

kherson [118]4 years ago
4 0

Answer:

$1.35

Step-by-step explanation:

9 x 0.15 = 1.35

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Which is a solution to the equation?<br> (x - 3)(x - 5) = 35<br> x= -8<br> x=-5<br> x=2<br> x = 10
JulijaS [17]

(x-3)(x-5)=35

Multiply the brackets together

x*x-5*x-3*x-3*5

x^2-8x+15=35

Move +35 to the other side. Sign changes from +35 to -35

x^2-8x+15-35=35-35

x^2-8x-20=0

(x-10)(x+2)=0

x-10=0     x+2=0

Move -10 to the other side. Sign changes from -10 to +10

x-10+10=0+10   x+2-2=0-2

 x=10                      x=-2

Answer: x=10

4 0
4 years ago
Read 2 more answers
What is the word phrase of 4/n?
juin [17]
Four divided by a number n.
I'm sure of it and I hope I helped.
7 0
3 years ago
I really need help on this problem its on khan academy 27÷(−9)=?
ladessa [460]

Answer: -3

Step-by-step explanation:

\frac{27}{-9} = -3 \\

We can check our work my multiplying -3 by -9 and see that it equals 27

-9*[\frac{27}{-9}  = -3 ]* -9\\27 = 27

8 0
3 years ago
X^=1/4 please help me pls
viva [34]
X^2=1/4

x=1/2 or -1/2
x=.5 or -.5
4 0
3 years ago
Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca
qwelly [4]

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

\frac{4}{52}

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

\frac{13}{52}

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

P = \frac{4}{52}  * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%

Thus total probability for the combined two cases will be 1.92%

7 0
3 years ago
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