(x-3)(x-5)=35
Multiply the brackets together
x*x-5*x-3*x-3*5
x^2-8x+15=35
Move +35 to the other side. Sign changes from +35 to -35
x^2-8x+15-35=35-35
x^2-8x-20=0
(x-10)(x+2)=0
x-10=0 x+2=0
Move -10 to the other side. Sign changes from -10 to +10
x-10+10=0+10 x+2-2=0-2
x=10 x=-2
Answer: x=10
Four divided by a number n.
I'm sure of it and I hope I helped.
Answer: -3
Step-by-step explanation:

We can check our work my multiplying -3 by -9 and see that it equals 27
![-9*[\frac{27}{-9} = -3 ]* -9\\27 = 27](https://tex.z-dn.net/?f=-9%2A%5B%5Cfrac%7B27%7D%7B-9%7D%20%20%3D%20-3%20%5D%2A%20-9%5C%5C27%20%3D%2027)
X^2=1/4
x=1/2 or -1/2
x=.5 or -.5
Answer:
1.92%
Step-by-step explanation:
The probability for first case, picking a queen out of deck, will be:

as there will be 4 queens in a deck, one of each suit.
For the second pick, the probability of picking a diamond card, will be:

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).
Thus the net probability for both cases will be:

Thus total probability for the combined two cases will be 1.92%