Question

X^2+-5x=0 i’m confused

Answer 1

Answer:

Therefore,

$x=0\ or\ x=5$

Step-by-step explanation:

Given:

$x^{2}+-5x=0$

To Solve:

x = ?

Solution:

Addition and Subtraction is explain by some examples say,

5 + 3 = 8

5  - 3 = 2

But in case,

5 + - 3 is also written as

5 -3 = 2

if it is

5 - - 3 then it becomes

5 +3 = 8

That means

"+" and "-" will become "-"

"-" and "-" will become "+"

"-" and "+" will become "-"

"+" and "+" will become "+"

Therefore,

$x^{2}+-5x=0$

will become

$x^{2}-5x=0$

Take common 'x' out then

$x(x-5)=0\\\\x = 0\ or\ x-5=0\\\\x=0\ or\ x=5$

Therefore,

$x=0\ or\ x=5$