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KengaRu [80]
2 years ago
11

Which equation goes with the graph

Mathematics
1 answer:
Rus_ich [418]2 years ago
3 0
Link is scam. literally cap. don’t use it or what do ever!
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Solve the any quality then identify the graph the solution -3x-3<6
Tanzania [10]

Answer:

Step-by-step explanation:

-3X-3<6

-3X<9

X>-3    (NOTICE THE SIGN CHANGE BECAUSE WE DIVIDED BY A NEGATIVE NUMBER)

(-3,00) INTERVAL NOTATION

7 0
3 years ago
Read 2 more answers
Which function does this graph correspond to?
tiny-mole [99]
ANSWER

The function that the given graph corresponds to is
f(x) = (x - 2)(x - 1)(x + 1)(x  + 2)



EXPLANATION

The given graph in the attachment has x-intercepts at

x =  - 2 ,x=-1,x=1  \:  \: and   \: \: x=2


These are the solutions of the polynomial function represented by the given graph.




We can write all these solutions as factors to obtain,

x  + 2  ,x + 1 ,x - 1   \:  \:and \:  \: x - 2


The product of all these factors gives us the function whose graph was drawn.


This implies that,

f(x) = (x - 2)(x - 1)(x + 1)(x  + 2)


Therefore the correct answer is option C.
7 0
3 years ago
Read 2 more answers
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
In the problem 62 × 45, what are the partial products?
Nana76 [90]
In the problem 62 times 45 the partial numbers are 6 and 5
4 0
3 years ago
Using the law of sines, find the solutions for the missing inputs.
SashulF [63]

\frac{a}{ \sin(a) }  =  \frac{b}{ \sin(b)  }
\frac{12}{ \sin(38) }  =  \frac{b}{ \sin(85) }
\frac{12}{ \sin(38) }  =  \frac{a}{ \sin(57) }
180 - (85 + 38) = 57
\frac{12}{ \sin(38) }  =  \frac{b}{ \sin(85) }
\sin(85)   \times  \frac{12}{ \sin(38) }  = b
\sin(57)   \times  \frac{12}{ \sin(38) }  = a
sorry for the order of steps
5 0
3 years ago
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