Explain whether continuing to increase light intensity will increase the rate of photosynthesis. Please help!

Biology

1 answer:

crimeas [40]4 years ago

6 0

Answer:

So in the case of a plant, a higher light intensity means more packets of light called “photons” are hitting the leaves. As you rise from low light intensity to higher light intensity, the rate of photosynthesis will increase because there is more light available to drive the reactions of photosynthesis.

Explanation:

If you continue to increase the intensity of light that a plant receives, what happens? The rate of photosynthesis increases with light intensity. The rate of photosynthesis decreases with light intensity. The rate of photosynthesis increases and then levels off.As light intensity increases (distance between lamp and plant decreases) the volume of oxygen (or the rate of bubble production) increases. This indicates that the rate of photosynthesis increases with light intensity.

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If I wanted to test whole milk using all of the indicators (biuret, benedicts, iodine and brown paper bag), what results would y

stellarik [79]

Whole milk will give a biuret positive, Benedict positive, iodine negative and brown paper bag test positive results.

<h3><u>Explanation:</u></h3>

Whole milk is obtained from mainly the dairy animals like cow, Buffalo etc. It contains different ingredients of diet and is considered as an ideal balanced diet for infants.

The Benedict's test is a test to identify the presence of reducing sugars. Milk contains reducing sugar lactose. This is why milk gives Benedict's positive result.

Biuret test also gives positive result because it is a test for protein and milk contains enough of this. The protein in milk is called casein.

The brown paper bag test is a test for lipid and its positive because the milk contains enough lipid. It depends on milk source.

The iodine test is a test for starch and milk isn't a good source of starch. So iodine test isn't positive.

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3 years ago

A man with free earlobes and the ability to taste PTC marries a woman with free earlobes and no ability to taste PTC. They have

Mrac [35]

Answer:

Father's genotype is T T, E e

Mother's genotype is t t, E e

Explanation:

Tasting PTC

Let the characters for tasting and not tasting PTC be T and t respectively.

Since all the children can taste PTC, it can be deduced that tasting PTC is a dominant trait.

The man will be homo-zygous dominant for tasting PTC while the woman is homo-zygous recessive for tasting PTC.

Genotype of man is T T and genotype of woman is t t

T T x t t = T t, , T t, T t; which is a 4:0 phenotype.

Earlobes:

Let the characters for Free and attached earlobes be E and e

Since both the man and woman have free earlobes and 3 out of 4 children have free earlobes, it can be deduced that free earlobes is dominant while attached earlobes is recessive.

The ratio of free to attached earlobes is 3:1

The man and the woman are both hetero-zygous dominant, E e for free earlobes, so that a cross between them will yield three hetero-zygous dominant for free earlobes and one homo-zygous recessive for attached earlobes.

E e x E e = E E, E e, E e, e e; which is a 3 : 1 phenotype.

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3 years ago

What is classified as neither a solid, liquid, or gas

atroni [7]

The answer i believe is a gel

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3 years ago

Read 2 more answers

The most superior segment of the upper limb is called the

Crazy boy [7]

The most upper part of the superior segment would be the brachial region.