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3 years ago

50 POINTS!!!!

Mathematics

1 answer:

tatiyna3 years ago

6 0

Answer:

90 cubic inches

Step-by-step explanation:

V = 1/3 · area of base · height

V = 1/3 · 18 · 15

V = 6 · 15

V = 90

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What is the reciprocal of -4

mario62 [17]

Answer: -4/1 = 1/-4

= 1/-4

Just flip the fraction:)

Step-by-step explanation:

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3 years ago

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Nvm don't answer this

Ludmilka [50]

Answer:

Step-by-step explanation:

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2 years ago

Iq scores are known to be normally distributed. the mean iq score is 100 and the standard deviation is 15. what percent of the p

kobusy [5.1K]

The 100%-Norm.Dist(value,mean,sd,true) percent of the population has an iq over 115

According to the statement

we have to find that the what percent of the population has an iq over 115.

And from given information,

the mean iq score is 100 and the standard deviation is 15.

And

Normal distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

And by use of this formula, we find the percentage of the population has an iq over 115.

Then the result will comes as 100%.

hence, 100%-Norm.Dist(value,mean,sd,true)

So, The 100%-Norm.Dist(value,mean,sd,true) percent of the population has an iq over 115.

Learn more about Normal distribution here

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1 year ago

Hello, can someone please help me with this problem. Thank you.

fredd [130]

Answer:

m = $-\frac{31}{18}$

Step-by-step explanation:

$m = \frac{16 - -15x}{0-18}$

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2 years ago

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85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C

Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = $\frac{85.87}{0.4360}$

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C Answer

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2 years ago