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k0ka [10]
3 years ago
12

The answer to question 4

Mathematics
1 answer:
Julli [10]3 years ago
8 0
If you show me the whole paper i can help you but first try
You might be interested in
What are effective elements to include in introductions? Check all that apply.
dlinn [17]

The effective elements to include in the introductions are statement of the topic, a relevant anecdote and a surprising fact about the topic. Therefore the option 1st, 2nd and 6th options are correct.

<h3>What is Introduction? </h3>

Introduction is the starting line or the opening hook or portion that attracts the readers attention which carries the relevant background of the information.

It is the statement which represents the main point of the following argument or the paragraphs.

There are many elements that included in the introductory part some of them are as follows:-

  • a statement of the topic
  • a relevant anecdote or tale
  • a surprising fact about the topic

Therefore the option 1st, 2nd and 6th options are correct.

Learn more about Introduction here:

brainly.com/question/3964580

#SPJ1

7 0
2 years ago
Read 2 more answers
4) Suppose y varies inversely with the SQUARE ROOT of x.
Savatey [412]

Answer:

Variation equation: y = k/√x

constant of variation: 200

Variation Equation by plugging the value of k: y = 200/√x

Step-by-step explanation:

If y varies inversely with the SQUARE ROOT of x, then;

y = k/√x

If  x = 4, y = 100.

100 = k/√4

100 = k/2

200 = k

k = 200

Substitute into the expression

y = k/√x

y = 200/√x

7 0
3 years ago
Evaluate the function at x=-1​
Oksana_A [137]

Answer:

y=0 when x=-1

Step-by-step explanation:

We look at the chart to see that there is a value for y when x equals negative 1.

According to the chart, y equals 0 when x=-1.

Therefore, the answer is 0.

4 0
3 years ago
A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
So, the probability that the sample proportion is less than 0.58 
= P(^p<0.58) 
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0... 
= P(z<-0.58) 
= P(z<0) - P(-0.58<z<0) 
= 0.5 - 0.2190 
= 0.281 
<span>So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58. </span>

4 0
3 years ago
I Need Help Please with this problem
goldenfox [79]

ΔACD is similar to ΔBCD by AA similarity theorem

AD/AC = BD/BC

x/5 = 4.2/6

6x = 21

x = 3.5

Hope this helps! ;)

3 0
3 years ago
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