Answer:
<h2><u>since </u><u>DE≅EF</u></h2>
<u>CD=</u><u>CF </u><u>(</u><u>cpct)</u>
<u>
</u>
<h2><u>hope</u><u> it</u><u> helps</u><u> you</u><u><</u><u>3</u></h2>
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
(9√25) /√50 = 9*5/√50 now simplify the denominator. √50=√25*√2=5√2
so (9*5)/(5√2) simplifies to 9/√2. To rationalize the denominator multiply both the numerator and the denominator by √2.
9√2/(√2*√2) = 9√2/2
Answer: d
Step-by-step explanation: formula is 1/2bh 14 times 6 is 84 divided by 2 is 42