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3 years ago

Simplify the expression: [15 +3(2) - 0]0 A) 4 B) -1 C) 0 D) 3

Mathematics

2 answers:

raketka [301]3 years ago

3 0

Answer:

The answer is C. So yeah.

Firlakuza [10]3 years ago

3 0

Answer:

Option C

Step-by-step explanation:

$[15 +3(2) - 0]0\\\\(15+6-0)0\\\\(21-0)0\\\\(21)0\\\\\boxed{0}$

Hope this helps.

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3 years ago

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3 years ago

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Talja [164]

Answer:

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Step-by-step explanation:

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3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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3 years ago